14x^2+70x-336=0

Solution for 14x^2+70x-336=0 equation:

14x^2+70x-336=0

a = 14; b = 70; c = -336;
Δ = b2-4ac
Δ = 702-4·14·(-336)
Δ = 23716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{23716}=154$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-154}{2*14}=\frac{-224}{28}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+154}{2*14}=\frac{84}{28}
=3
$